To find the solution for the system of equations given in the table, we need to look for a point where the y-values for both equations are equal for the same x-value.
From the table:
-
For \( x = 0 \):
- \( y = 2(0) - 5 = -5 \)
- \( y = 0 - 3 = -3 \)
-
For \( x = 1 \):
- \( y = 2(1) - 5 = -3 \)
- \( y = 1 - 3 = -2 \)
-
For \( x = 2 \):
- \( y = 2(2) - 5 = -1 \)
- \( y = 2 - 3 = -1 \)
-
For \( x = 3 \):
- \( y = 2(3) - 5 = 1 \)
- \( y = 3 - 3 = 0 \)
The only point where the y-values for both equations are equal is at \( (2, -1) \).
Therefore, the solution for the system of equations is \( \boxed{(2, -1)} \).