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Use the table to answer the question. x Substituted Evaluate True Statement? 7−11−−√ 7 11−7–√ 7+11−−√ 11+7–√ For the quadratic...Question
Use the table to answer the question.
x Substituted Evaluate True Statement?
7−11−−√
7
11−7–√
7+11−−√
11+7–√
For the quadratic equation (x−7)2=11, complete the table by testing each of the given values to determine whether it is a solution. Identify the two solutions to the quadratic equation.
(1 point)
The smaller of the two solutions is x=
x
=
. The larger of the two solutions is x=
x
=
.
x Substituted Evaluate True Statement?
7−11−−√
7
11−7–√
7+11−−√
11+7–√
For the quadratic equation (x−7)2=11, complete the table by testing each of the given values to determine whether it is a solution. Identify the two solutions to the quadratic equation.
(1 point)
The smaller of the two solutions is x=
x
=
. The larger of the two solutions is x=
x
=
.
Answers
Answer
whats the two number answers
Answered by
GPT-4o mini
To solve the quadratic equation \((x-7)^2 = 11\), we first need to find the solutions by taking the square root of both sides.
Step 1: Rewrite the equation
\[
(x - 7)^2 = 11
\]
Step 2: Take the square root of both sides
\[
x - 7 = \pm \sqrt{11}
\]
Step 3: Solve for \(x\)
1. For the positive square root:
\[
x - 7 = \sqrt{11} \implies x = 7 + \sqrt{11}
\]
2. For the negative square root:
\[
x - 7 = -\sqrt{11} \implies x = 7 - \sqrt{11}
\]
Now, we have our two solutions:
1. \(x = 7 + \sqrt{11}\) (approximately 10.32)
2. \(x = 7 - \sqrt{11}\) (approximately 3.68)
Identifying the smaller and larger solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\).
- The larger solution is \(x = 7 + \sqrt{11}\).
Thus:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
### Answers:
The smaller of the two solutions is \(x = 7 - \sqrt{11}\), and the larger of the two solutions is \(x = 7 + \sqrt{11}\).
Step 1: Rewrite the equation
\[
(x - 7)^2 = 11
\]
Step 2: Take the square root of both sides
\[
x - 7 = \pm \sqrt{11}
\]
Step 3: Solve for \(x\)
1. For the positive square root:
\[
x - 7 = \sqrt{11} \implies x = 7 + \sqrt{11}
\]
2. For the negative square root:
\[
x - 7 = -\sqrt{11} \implies x = 7 - \sqrt{11}
\]
Now, we have our two solutions:
1. \(x = 7 + \sqrt{11}\) (approximately 10.32)
2. \(x = 7 - \sqrt{11}\) (approximately 3.68)
Identifying the smaller and larger solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\).
- The larger solution is \(x = 7 + \sqrt{11}\).
Thus:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
### Answers:
The smaller of the two solutions is \(x = 7 - \sqrt{11}\), and the larger of the two solutions is \(x = 7 + \sqrt{11}\).
Answered by
GPT-4o mini
To provide the two numerical answers for \(x = 7 - \sqrt{11}\) and \(x = 7 + \sqrt{11}\), we can calculate them as follows:
1. Calculate \(7 - \sqrt{11}\):
- The approximate value of \(\sqrt{11} \approx 3.3166\).
- Therefore, \(7 - \sqrt{11} \approx 7 - 3.3166 \approx 3.6834\).
2. Calculate \(7 + \sqrt{11}\):
- Continuing with \(\sqrt{11} \approx 3.3166\).
- Thus, \(7 + \sqrt{11} \approx 7 + 3.3166 \approx 10.3166\).
So, rounded to two decimal points:
- The smaller solution is approximately \(3.68\).
- The larger solution is approximately \(10.32\).
Final answers:
- The smaller of the two solutions is \(x \approx 3.68\).
- The larger of the two solutions is \(x \approx 10.32\).
1. Calculate \(7 - \sqrt{11}\):
- The approximate value of \(\sqrt{11} \approx 3.3166\).
- Therefore, \(7 - \sqrt{11} \approx 7 - 3.3166 \approx 3.6834\).
2. Calculate \(7 + \sqrt{11}\):
- Continuing with \(\sqrt{11} \approx 3.3166\).
- Thus, \(7 + \sqrt{11} \approx 7 + 3.3166 \approx 10.3166\).
So, rounded to two decimal points:
- The smaller solution is approximately \(3.68\).
- The larger solution is approximately \(10.32\).
Final answers:
- The smaller of the two solutions is \(x \approx 3.68\).
- The larger of the two solutions is \(x \approx 10.32\).
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