To solve the quadratic equation \((x - 7)^2 = 11\), we'll first find the solutions by taking the square root of both sides.
- Start by rewriting the equation: \[(x - 7)^2 = 11\]
- Take the square root of both sides: \[x - 7 = \pm \sqrt{11}\]
This leads to two equations: \[x - 7 = \sqrt{11}\] \[x - 7 = -\sqrt{11}\]
- Solve for \(x\) in each case:
- For \(x - 7 = \sqrt{11}\): \[x = 7 + \sqrt{11}\]
- For \(x - 7 = -\sqrt{11}\): \[x = 7 - \sqrt{11}\]
Now we have the two solutions:
- The smaller solution is \(x = 7 - \sqrt{11}\)
- The larger solution is \(x = 7 + \sqrt{11}\)
We can approximate \(\sqrt{11}\): \(\sqrt{11} \approx 3.3166\)
Thus:
- The smaller solution: \[x \approx 7 - 3.3166 \approx 3.6834\]
- The larger solution: \[x \approx 7 + 3.3166 \approx 10.3166\]
However, for exact values:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
Final Answer: The smaller of the two solutions is \(x = 7 - \sqrt{11}\). The larger of the two solutions is \(x = 7 + \sqrt{11}\).