To solve the quadratic equation \((x - 7)^2 = 11\), we first need to find the values of \(x\) that satisfy this equation.
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Start by taking the square root of both sides: \[ x - 7 = \pm \sqrt{11} \]
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Now, solve for \(x\): \[ x = 7 + \sqrt{11} \quad \text{and} \quad x = 7 - \sqrt{11} \]
These two values are the solutions to the equation.
Now, approximate \(\sqrt{11}\): \[ \sqrt{11} \approx 3.3166 \]
Thus, we can find the two solutions:
- For \(x = 7 + \sqrt{11}\): \[ x \approx 7 + 3.3166 \approx 10.3166 \]
- For \(x = 7 - \sqrt{11}\): \[ x \approx 7 - 3.3166 \approx 3.6834 \]
Based on the approximations, we conclude:
- The smaller solution is \(x \approx 3.6834\).
- The larger solution is \(x \approx 10.3166\).
Thus, filling in the blanks from your question:
The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
The larger of the two solutions is \(x = 7 + \sqrt{11}\).