Use the table to answer the question.

x Substituted Evaluate True Statement?
12
24
36
48
When set off, a certain firework follows the path of the quadratic function h=−2536x2+1623x , where:

h= the height of the firework in feet.
x= the horizontal distance it travels in feet.
To determine how far the firework will travel before reaching the ground, determine which value of x in table is a solution to the equation 0=−2536x2+1623x .

(1 point)
Responses

48 feet
48 feet

24 feet
24 feet

36 feet
36 feet

12 feet
12 feet
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1 answer

To determine how far the firework travels before reaching the ground, we need to find the values of \( x \) that satisfy the equation \( 0 = -2536x^2 + 1623x \). This can be rewritten in standard quadratic form as:

\[ -2536x^2 + 1623x = 0 \]

Factoring out \( x \) gives us:

\[ x(-2536x + 1623) = 0 \]

This implies two solutions:

  1. \( x = 0 \) (which corresponds to the start of the firework launch)
  2. \( -2536x + 1623 = 0 \)

Now, we can solve for \( x \):

\[ -2536x + 1623 = 0 \ 2536x = 1623 \ x = \frac{1623}{2536} \]

Calculating \( \frac{1623}{2536} \) gives approximately \( 0.6398 \) feet, which is not one of the provided responses.

Given the choices of 12 feet, 24 feet, 36 feet, and 48 feet, we will substitute these values back into the original equation to check which one makes \( h = 0 \):

  1. For \( x = 12 \): \[ h = -2536(12)^2 + 1623(12) \] \[ h = -2536(144) + 1623(12) \] \[ h = -364224 + 19476 = -344748 \quad (\text{not zero}) \]

  2. For \( x = 24 \): \[ h = -2536(24)^2 + 1623(24) \] \[ h = -2536(576) + 1623(24) \] \[ h = -1460160 + 38952 = -1421208 \quad (\text{not zero}) \]

  3. For \( x = 36 \): \[ h = -2536(36)^2 + 1623(36) \] \[ h = -2536(1296) + 1623(36) \] \[ h = -3288960 + 58428 = -3230532 \quad (\text{not zero}) \]

  4. For \( x = 48 \): \[ h = -2536(48)^2 + 1623(48) \] \[ h = -2536(2304) + 1623(48) \] \[ h = -5832960 + 77808 = -5755152 \quad (\text{not zero}) \]

None of the substituted values make \( h = 0 \), meaning that the fireworks will not reach the ground at any of these given horizontal distances.

However, if we were to state which \( x \) is equal to reaching the height of 0 based on the evaluations, then these values are not directly derived from the equation being solved.

Thus, all tested \( x \) values yield negative heights, indicating the firework stays in the air without returning to ground at precisely those set distances, since no height evaluations returned true statements regarding touching ground. It means there is no solution among the provided options or the distances require further polynomial inputs.