To determine whether a given value is a solution for the quadratic equation −2x^2−3x+2=0, we substitute the value into the equation and evaluate whether it makes the equation true.
Let's complete the table for the given values of x:
x | Substituted | Evaluate | True Statement?
___________________________________________________
−34 |-2(-34)^2−3(-34)+2=0 |False| No
−12 |-2(-12)^2−3(-12)+2=0 |False| No
12 |-2(12)^2−3(12)+2=0 |True | Yes
From the table, we can see that only x=12 is a solution to the quadratic equation.
Use the table to answer the question.
x Substituted Evaluate True Statement?
−34
−12
12
For the quadratic equation −2x2−3x+2=0
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of the values is in the solution set.
(1 point)
Only x=
is in the solution set.
1 answer
1 answer