Use the table to answer the question.

x f(x)
g(x)

−2
−1
−1

−1
34
0
0 1 1
1 114
2
2 3 3
Compare the functions f(x)
and g(x)
. When is f(x)
greater than g(x)
?

1 answer

To compare the functions \( f(x) \) and \( g(x) \) using the provided data:

\[ \begin{array}{c|c|c} x & f(x) & g(x) \ \hline -2 & -1 & -1 \ -1 & 34 & 0 \ 0 & 1 & 1 \ 1 & 114 & 2 \ 2 & 3 & 3 \ \end{array} \]

Let's analyze the values of \( f(x) \) and \( g(x) \) for each given \( x \):

  1. For \( x = -2 \):

    • \( f(-2) = -1 \)
    • \( g(-2) = -1 \)
    • \( f(-2) \) is not greater than \( g(-2) \).
  2. For \( x = -1 \):

    • \( f(-1) = 34 \)
    • \( g(-1) = 0 \)
    • \( f(-1) \) is greater than \( g(-1) \).
  3. For \( x = 0 \):

    • \( f(0) = 1 \)
    • \( g(0) = 1 \)
    • \( f(0) \) is not greater than \( g(0) \).
  4. For \( x = 1 \):

    • \( f(1) = 114 \)
    • \( g(1) = 2 \)
    • \( f(1) \) is greater than \( g(1) \).
  5. For \( x = 2 \):

    • \( f(2) = 3 \)
    • \( g(2) = 3 \)
    • \( f(2) \) is not greater than \( g(2) \).

Summary:

  • \( f(x) > g(x) \) when:
    • \( x = -1 \)
    • \( x = 1 \)

Therefore, \( f(x) \) is greater than \( g(x) \) for \( x = -1 \) and \( x = 1 \).