To determine which graph accurately represents the function \( f(x) = 12x + 3 \) for the input values of \( -4, -2, 0, 2, \) and \( 4 \), we first need to calculate the outputs for each of these inputs.
-
For \( x = -4 \):
\[
f(-4) = 12(-4) + 3 = -48 + 3 = -45
\]
-
For \( x = -2 \):
\[
f(-2) = 12(-2) + 3 = -24 + 3 = -21
\]
-
For \( x = 0 \):
\[
f(0) = 12(0) + 3 = 0 + 3 = 3
\]
-
For \( x = 2 \):
\[
f(2) = 12(2) + 3 = 24 + 3 = 27
\]
-
For \( x = 4 \):
\[
f(4) = 12(4) + 3 = 48 + 3 = 51
\]
Now we can summarize the input-output pairs:
\[
\begin{array}{c|c}
x & f(x) \
\hline
-4 & -45 \
-2 & -21 \
0 & 3 \
2 & 27 \
4 & 51 \
\end{array}
\]
Next, let's analyze the results:
- The output for \( x = -4 \) is \( -45 \).
- The output for \( x = -2 \) is \( -21 \).
- The output for \( x = 0 \) is \( 3 \).
- The output for \( x = 2 \) is \( 27 \).
- The output for \( x = 4 \) is \( 51 \).
Now, let's see which points are plotted based on these calculations:
- \( (-4, -45) \)
- \( (-2, -21) \)
- \( (0, 3) \)
- \( (2, 27) \)
- \( (4, 51) \)
You should look for a graph that passes through these specific points. The last graph with axises ranging from \( 0 \) to \( 7 \) in increments of \( 1 \) cannot represent these points accurately since the \( x \) values are outside that range.
You should choose the one of the first three options (A, B, or C) that visualizes the points plotted at the outputs calculated above. Since I can't see the options without images, you should select the graph in the images which shows a line passing through the calculated points while maintaining the appropriate scales on both axes.
Thus, without specific visual representations, I’d suggest confirming from your available options which graph correctly includes those points.