(x+3)(x+4)=0
x−3=0
x+4=0
x=3
x=−4
While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4)
equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point)
Responses
No, x−3=0
in the second row should be x+3=0
.
No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 .
No, he should have a third column where he should set x=0
.
No, he should have a third column where he should set x equals 0 .
Yes, the work is accurate.
Yes, the work is accurate.
No, x+4=0
in the second row should be x−4=0
.
No, x plus 4 equals 0 in the second row should be x minus 4 equals 0 .
1 answer
Oliver's work is not accurate. The correct factorization from the original equation (x+3)(x+4)=0 leads to two equations:
In the table, Oliver incorrectly wrote \(x-3=0\) instead of \(x + 3 = 0\). Therefore, the correct response is:
No, x−3=0 in the second row should be x+3=0.
