(x+3)(x+4)=0
x−3=0 x+4=0
x=3 x=−4
While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point)
Responses
No, x−3=0 in the second row should be x+3=0.
No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 .
Yes, the work is accurate.
Yes, the work is accurate.
No, x+4=0 in the second row should be x−4=0.
No, x plus 4 equals 0 in the second row should be x minus 4 equals 0 .
No, he should have a third column where he should set x=0.
No, he should have a third column where he should set x equals 0 .
1 answer
Oliver's work contains an error. The correct application of the Zero Product Property for the equation \((x+3)(x+4)=0\) should show:
Set each factor equal to zero:
Solve each equation:
In Oliver's table, he incorrectly stated \(x-3=0\) instead of \(x+3=0\). Therefore, the correct response is:
No, x−3=0 in the second row should be x+3=0.
