Use the table to answer the question.

(x+3)(x+4)=0
x−3=0 x+4=0
x=3 x=−4While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point)
Responses

No, x+4=0 in the second row should be x−4=0.
No, x plus 4 equals 0 in the second row should be x minus 4 equals 0 .

No, x−3=0 in the second row should be x+3=0.
No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 .

No, he should have a third column where he should set x=0.
No, he should have a third column where he should set x equals 0 .

Yes, the work is accurate.
Yes, the work is accurate.
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1 answer

Oliver’s work is not accurate. The correct factorization set from the equation \((x+3)(x+4)=0\) would lead to the equations \(x+3=0\) and \(x+4=0\).

In the provided table, Oliver has correctly listed the factors, but there is a mistake in how the values of \(x\) are stated.

The first equation \(x−3=0\) is incorrect; it should indeed be \(x+3=0\).

Therefore, the correct choice is:

No, x−3=0 in the second row should be x+3=0.

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