(x+3)(x+4)=0
x−3=0 x+4=0
x=3 x=−4While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver’s work accurate?(1 point)
Responses
No, x+4=0 in the second row should be x−4=0.
No, x plus 4 equals 0 in the second row should be x minus 4 equals 0 .
No, x−3=0 in the second row should be x+3=0.
No, x minus 3 equals 0 in the second row should be x plus 3 equals 0 .
No, he should have a third column where he should set x=0.
No, he should have a third column where he should set x equals 0 .
Yes, the work is accurate.
Yes, the work is accurate.
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1 answer
Oliver’s work is not accurate. The correct factorization set from the equation \((x+3)(x+4)=0\) would lead to the equations \(x+3=0\) and \(x+4=0\).
In the provided table, Oliver has correctly listed the factors, but there is a mistake in how the values of \(x\) are stated.
The first equation \(x−3=0\) is incorrect; it should indeed be \(x+3=0\).
Therefore, the correct choice is:
No, x−3=0 in the second row should be x+3=0.
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