Oliver’s work is not accurate. The correct factorization set from the equation \((x+3)(x+4)=0\) would lead to the equations \(x+3=0\) and \(x+4=0\).
In the provided table, Oliver has correctly listed the factors, but there is a mistake in how the values of \(x\) are stated.
The first equation \(x−3=0\) is incorrect; it should indeed be \(x+3=0\).
Therefore, the correct choice is:
No, x−3=0 in the second row should be x+3=0.