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Use the table to answer the question. Write the exponential equation that contains the points shown in the table. x y โ1 10 2 2...Question
Use the table to answer the question.
Write the exponential equation that contains the points shown in the table.
x y
โ1
โ
1
200
2 0.675
(1 point)
The equation is $$y=ยท.
Write the exponential equation that contains the points shown in the table.
x y
โ1
โ
1
200
2 0.675
(1 point)
The equation is $$y=ยท.
Answers
Answered by
GPT-4o mini
To find the exponential equation that fits the points shown in the table, we need to assume the form of the exponential function, which is typically given as:
\[
y = ab^x
\]
Where:
- \( a \) is the initial value (when \( x = 0 \)),
- \( b \) is the base (growth or decay factor).
From the provided points:
1. For \( x = -1, y = 200 \)
2. For \( x = 2, y = 0.675 \)
We can use these points to create two equations.
### Step 1: Set Up the Equations
From the first point \( (-1, 200) \):
\[
200 = ab^{-1}
\]
This can be rewritten as:
\[
ab^{-1} = 200 \quad \Rightarrow \quad \frac{a}{b} = 200 \quad \text{(Equation 1)}
\]
From the second point \( (2, 0.675) \):
\[
0.675 = ab^2 \quad \text{(Equation 2)}
\]
### Step 2: Solve the Equations
Now we have a system of equations:
1. \( \frac{a}{b} = 200 \)
2. \( a b^2 = 0.675 \)
From Equation 1, we can express \( a \) in terms of \( b \):
\[
a = 200b
\]
Now, substitute \( a \) into Equation 2:
\[
200b \cdot b^2 = 0.675
\]
This simplifies to:
\[
200b^3 = 0.675
\]
Now, solve for \( b \):
\[
b^3 = \frac{0.675}{200} = 0.003375
\]
Taking the cube root of both sides:
\[
b = \sqrt[3]{0.003375} \approx 0.15
\]
### Step 3: Find \( a \)
Now substitute \( b \) back into the equation for \( a \):
\[
a = 200b \approx 200 \cdot 0.15 = 30
\]
### Final Equation
Thus, the exponential equation becomes:
\[
y = 30(0.15)^x
\]
So, we can write the equation as:
\[
\boxed{y = 30(0.15)^x}
\]
This is the exponential equation that passes through the given points.
\[
y = ab^x
\]
Where:
- \( a \) is the initial value (when \( x = 0 \)),
- \( b \) is the base (growth or decay factor).
From the provided points:
1. For \( x = -1, y = 200 \)
2. For \( x = 2, y = 0.675 \)
We can use these points to create two equations.
### Step 1: Set Up the Equations
From the first point \( (-1, 200) \):
\[
200 = ab^{-1}
\]
This can be rewritten as:
\[
ab^{-1} = 200 \quad \Rightarrow \quad \frac{a}{b} = 200 \quad \text{(Equation 1)}
\]
From the second point \( (2, 0.675) \):
\[
0.675 = ab^2 \quad \text{(Equation 2)}
\]
### Step 2: Solve the Equations
Now we have a system of equations:
1. \( \frac{a}{b} = 200 \)
2. \( a b^2 = 0.675 \)
From Equation 1, we can express \( a \) in terms of \( b \):
\[
a = 200b
\]
Now, substitute \( a \) into Equation 2:
\[
200b \cdot b^2 = 0.675
\]
This simplifies to:
\[
200b^3 = 0.675
\]
Now, solve for \( b \):
\[
b^3 = \frac{0.675}{200} = 0.003375
\]
Taking the cube root of both sides:
\[
b = \sqrt[3]{0.003375} \approx 0.15
\]
### Step 3: Find \( a \)
Now substitute \( b \) back into the equation for \( a \):
\[
a = 200b \approx 200 \cdot 0.15 = 30
\]
### Final Equation
Thus, the exponential equation becomes:
\[
y = 30(0.15)^x
\]
So, we can write the equation as:
\[
\boxed{y = 30(0.15)^x}
\]
This is the exponential equation that passes through the given points.
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