Use the table to answer the question.

Write the exponential equation that contains the points shown in the table.

x y
−1

1
200
2 0.675
(1 point)
The equation is $$y=·.

1 answer

To find the exponential equation that fits the points shown in the table, we need to assume the form of the exponential function, which is typically given as:

\[ y = ab^x \]

Where:

  • \( a \) is the initial value (when \( x = 0 \)),
  • \( b \) is the base (growth or decay factor).

From the provided points:

  1. For \( x = -1, y = 200 \)
  2. For \( x = 2, y = 0.675 \)

We can use these points to create two equations.

Step 1: Set Up the Equations

From the first point \( (-1, 200) \):

\[ 200 = ab^{-1} \]

This can be rewritten as:

\[ ab^{-1} = 200 \quad \Rightarrow \quad \frac{a}{b} = 200 \quad \text{(Equation 1)} \]

From the second point \( (2, 0.675) \):

\[ 0.675 = ab^2 \quad \text{(Equation 2)} \]

Step 2: Solve the Equations

Now we have a system of equations:

  1. \( \frac{a}{b} = 200 \)
  2. \( a b^2 = 0.675 \)

From Equation 1, we can express \( a \) in terms of \( b \):

\[ a = 200b \]

Now, substitute \( a \) into Equation 2:

\[ 200b \cdot b^2 = 0.675 \]

This simplifies to:

\[ 200b^3 = 0.675 \]

Now, solve for \( b \):

\[ b^3 = \frac{0.675}{200} = 0.003375 \]

Taking the cube root of both sides:

\[ b = \sqrt[3]{0.003375} \approx 0.15 \]

Step 3: Find \( a \)

Now substitute \( b \) back into the equation for \( a \):

\[ a = 200b \approx 200 \cdot 0.15 = 30 \]

Final Equation

Thus, the exponential equation becomes:

\[ y = 30(0.15)^x \]

So, we can write the equation as:

\[ \boxed{y = 30(0.15)^x} \]

This is the exponential equation that passes through the given points.

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