Asked by I
Use the table to answer the question.
Wave λ
(m) vw
(m/s)
L 120 600
M 150 600
N 100 600
O 50 600
The table shows information about four waves. Which wave has the lowest frequency?
(1 point)
Responses
wave O
wave O
wave M
wave M
wave L
wave L
wave N
Wave λ
(m) vw
(m/s)
L 120 600
M 150 600
N 100 600
O 50 600
The table shows information about four waves. Which wave has the lowest frequency?
(1 point)
Responses
wave O
wave O
wave M
wave M
wave L
wave L
wave N
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which wave has the lowest frequency, we can use the formula for frequency (f):
\[ f = \frac{v}{\lambda} \]
where \( v \) is the speed of the wave, and \( \lambda \) is the wavelength.
Since all the waves listed have the same speed \( v = 600 \, \text{m/s} \), we can simply calculate the frequency for each wave using their respective wavelengths:
1. For wave L (\( \lambda = 120 \, \text{m} \)):
\[
f_L = \frac{600}{120} = 5 \, \text{Hz}
\]
2. For wave M (\( \lambda = 150 \, \text{m} \)):
\[
f_M = \frac{600}{150} = 4 \, \text{Hz}
\]
3. For wave N (\( \lambda = 100 \, \text{m} \)):
\[
f_N = \frac{600}{100} = 6 \, \text{Hz}
\]
4. For wave O (\( \lambda = 50 \, \text{m} \)):
\[
f_O = \frac{600}{50} = 12 \, \text{Hz}
\]
Now we can compare the frequencies:
- Wave L: 5 Hz
- Wave M: 4 Hz
- Wave N: 6 Hz
- Wave O: 12 Hz
The wave with the lowest frequency is **wave M** with a frequency of 4 Hz.
So, the answer is:
**wave M**
\[ f = \frac{v}{\lambda} \]
where \( v \) is the speed of the wave, and \( \lambda \) is the wavelength.
Since all the waves listed have the same speed \( v = 600 \, \text{m/s} \), we can simply calculate the frequency for each wave using their respective wavelengths:
1. For wave L (\( \lambda = 120 \, \text{m} \)):
\[
f_L = \frac{600}{120} = 5 \, \text{Hz}
\]
2. For wave M (\( \lambda = 150 \, \text{m} \)):
\[
f_M = \frac{600}{150} = 4 \, \text{Hz}
\]
3. For wave N (\( \lambda = 100 \, \text{m} \)):
\[
f_N = \frac{600}{100} = 6 \, \text{Hz}
\]
4. For wave O (\( \lambda = 50 \, \text{m} \)):
\[
f_O = \frac{600}{50} = 12 \, \text{Hz}
\]
Now we can compare the frequencies:
- Wave L: 5 Hz
- Wave M: 4 Hz
- Wave N: 6 Hz
- Wave O: 12 Hz
The wave with the lowest frequency is **wave M** with a frequency of 4 Hz.
So, the answer is:
**wave M**
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