Use the table to answer the question. The table lists the value of a car each year after it is purchased.

Year 0 1 2 3 4
Value ($) 54,000 51,840 49,766 47,776 45,865

Determine whether the decreasing value can be modeled by a linear decay function or an exponential decay function, and why. (1 point) Responses exponential decay function; the value decreases by 4% per year, which is a constant percent rate of change exponential decay function; the value decreases by 4% per year, which is a constant percent rate of change exponential decay function; the value decreases by $6,000 per year, which is a constant percent rate of change exponential decay function; the value decreases by $6,000 per year, which is a constant percent rate of change linear decay function; the value decreases by 0.96 per year, which is a constant percent rate of change linear decay function; the value decreases by 0.96 per year, which is a constant percent rate of change linear decay function; the value decreases by 96% per year, which is a constant percent rate of change linear decay function; the value decreases by 96% per year, which is a constant percent rate of change

1 answer

To determine whether the decreasing value of the car can be modeled by a linear decay function or an exponential decay function, we need to analyze how the value changes each year.

From the table:

  • Year 0: $54,000
  • Year 1: $51,840
  • Year 2: $49,766
  • Year 3: $47,776
  • Year 4: $45,865

To see if this represents a linear or exponential decay, we can look at the percentage decrease year over year:

  1. From Year 0 to Year 1: \[ \text{Decrease} = 54,000 - 51,840 = 2,160 \] \[ \text{Percentage decrease} = \frac{2,160}{54,000} \times 100 \approx 4% \]

  2. From Year 1 to Year 2: \[ \text{Decrease} = 51,840 - 49,766 = 2,074 \] \[ \text{Percentage decrease} = \frac{2,074}{51,840} \times 100 \approx 4% \]

  3. From Year 2 to Year 3: \[ \text{Decrease} = 49,766 - 47,776 = 1,990 \] \[ \text{Percentage decrease} = \frac{1,990}{49,766} \times 100 \approx 4% \]

  4. From Year 3 to Year 4: \[ \text{Decrease} = 47,776 - 45,865 = 1,911 \] \[ \text{Percentage decrease} = \frac{1,911}{47,776} \times 100 \approx 4% \]

In each calculation, the value decreases by approximately 4% every year. This indicates that the car's value is decreasing by a constant percentage, which is characteristic of exponential decay.

Therefore, the correct response is: exponential decay function; the value decreases by 4% per year, which is a constant percent rate of change.