To find the system of linear equations represented by the table of values, we need to determine the equations for both \( y_a \) and \( y_b \) based on the given pairs of \( (x, y) \).
Analyzing \( y_a \)
- From the table:
- When \( x = 0 \), \( y_a = 3 \)
- When \( x = 1 \), \( y_a = 5 \)
- When \( x = 2 \), \( y_a = 7 \)
The change in \( y_a \) as \( x \) increases by 1 is:
- From 3 to 5 (an increase of 2)
- From 5 to 7 (an increase of 2)
This indicates the slope \( m_a = 2 \).
Using the point-slope form \( y - y_1 = m(x - x_1) \): Using the point \( (0, 3) \): \[ y_a - 3 = 2(x - 0) \] \[ y_a = 2x + 3 \]
So, the equation for \( y_a \) is: \[ y_a = 2x + 3 \]
Analyzing \( y_b \)
- From the table:
- When \( x = 0 \), \( y_b = -2 \)
- When \( x = 1 \), \( y_b = 1 \)
- When \( x = 2 \), \( y_b = 4 \)
The change in \( y_b \) as \( x \) increases by 1 is:
- From -2 to 1 (an increase of 3)
- From 1 to 4 (an increase of 3)
This indicates the slope \( m_b = 3 \).
Using the point-slope form \( y - y_1 = m(x - x_1) \): Using the point \( (0, -2) \): \[ y_b + 2 = 3(x - 0) \] \[ y_b = 3x - 2 \]
So, the equation for \( y_b \) is: \[ y_b = 3x - 2 \]
Conclusion
In conclusion, the system of linear equations is:
- \( y_a = 2x + 3 \)
- \( y_b = 3x - 2 \)
Among the options given, the correct answer is: {y=2x+3 y=3x−2}