Use the table to answer the question.

Sydney bought a new car for $32,000.00. If the car depreciates in value by 8% each year, the situation can be modeled by the equation f(x)=32,000(0.92)x
. Complete the table to find the value of the car to the nearest cent after three years.

The value of the car after three years is $ ______.

(1 point)
Responses

$24,918.02
$24,918.02

$27,048.80
$27,048.80

$32,000.00
$32,000.00

$24,440.00
$24,440.00
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1 answer

To find the value of the car after three years using the given equation \( f(x) = 32,000(0.92)^x \):

  1. Set \( x = 3 \) (since we're calculating the value after three years).
  2. Substitute \( x \) into the equation:

\[ f(3) = 32,000(0.92)^3 \]

  1. Calculate \( (0.92)^3 \):

\[ (0.92)^3 \approx 0.778688 \]

  1. Now, substitute this value back into the equation:

\[ f(3) = 32,000 \times 0.778688 \approx 24,916.00 \]

Rounding to the nearest cent gives us:

\[ f(3) \approx 24,916.00 \]

Therefore, the value of the car after three years is approximately $24,916.00. Since this may not match the given options exactly due to rounding, it looks like the closest option would be $24,918.02.

So the value of the car after three years is $24,918.02.