To find \( P(\text{blue or medium}) \), we can use the principle of inclusion-exclusion:
\[ P(\text{blue or medium}) = P(\text{blue}) + P(\text{medium}) - P(\text{blue and medium}) \]
Now, let's calculate each of these probabilities from the table:
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Calculate \( P(\text{blue}) \):
- Total number of blue items = 6 (from the TOTAL column for Blue)
- Total number of items = 30
- So, \( P(\text{blue}) = \frac{6}{30} \)
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Calculate \( P(\text{medium}) \):
- Total number of medium items = 7 (from the TOTAL column for Medium)
- So, \( P(\text{medium}) = \frac{7}{30} \)
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Calculate \( P(\text{blue and medium}) \):
- Blue and medium = 1 (from the cell in the table corresponding to Blue and Medium)
- So, \( P(\text{blue and medium}) = \frac{1}{30} \)
Now, we can combine these results:
\[ P(\text{blue or medium}) = \frac{6}{30} + \frac{7}{30} - \frac{1}{30} = \frac{6 + 7 - 1}{30} = \frac{12}{30} \]
Thus, \( P(\text{blue or medium}) = \frac{12}{30} \).
The correct response is \( \frac{12}{30} \).