To find \( P(\text{Blue or Medium}) \), we can use the principle of inclusion-exclusion:
\[ P(\text{Blue or Medium}) = P(\text{Blue}) + P(\text{Medium}) - P(\text{Blue and Medium}) \]
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Calculate \( P(\text{Blue}) \):
There are 6 blue items out of 30 total items:\[ P(\text{Blue}) = \frac{6}{30} \]
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Calculate \( P(\text{Medium}) \):
We need to find the total number of medium-sized items. The table shows:- Medium Yellow: 4
- Medium Blue: 1
- Medium Red: 2
Total Medium = 4 + 1 + 2 = 7
So,
\[ P(\text{Medium}) = \frac{7}{30} \]
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Calculate \( P(\text{Blue and Medium}) \):
From the table, there is 1 blue medium item.\[ P(\text{Blue and Medium}) = \frac{1}{30} \]
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Now substitute into the formula:
\[ P(\text{Blue or Medium}) = P(\text{Blue}) + P(\text{Medium}) - P(\text{Blue and Medium}) \]
\[ P(\text{Blue or Medium}) = \frac{6}{30} + \frac{7}{30} - \frac{1}{30} = \frac{6 + 7 - 1}{30} = \frac{12}{30} \]
So, the answer is:
\(\frac{12}{30}\)
Thus, the correct option is:
12/30