First, we need to find the total frequency of all consonants (K, N, D).
Total frequency of consonants = 120 (K) + 105 (N) + 135 (D) = 360
Total frequency of all outcomes = 120 (K) + 140 (I) + 105 (N) + 135 (D) = 500
Therefore, the probability of the spinner stopping on a consonant on the next spin is:
Probability = Total frequency of consonants / Total frequency of all outcomes
Probability = 360 / 500
Probability = 0.72
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.72.
So, the correct answer is C. 0.72.
Use the table to answer the question.
Outcomes | K | I | N | D |
Frequency | 120 | 140 | 105 | 135 |
A spinner is divided into 4 sections labeled as K, I, N, D. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?
A. 0.24
B. 0.45
C. 0.72
D. 0.28
1 answer