The total frequency of all outcomes is 500 (120 + 140 + 105 + 135), and the frequencies of the consonants (K, N, D) is 365 (120 + 105 + 135).
The probability of landing on a consonant is the frequency of consonants divided by the total frequency:
P(consonant) = 365/500 = 0.73
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.73, which is closest to option 0.72.
So, the answer is 0.72.
Use the table to answer the question.
Outcomes K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K , I , N , D . Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?
(1 point)
Responses
0.45
0.45
0.24
0.24
0.28
0.28
0.72
0.72
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