To find the approximate probability that the spinner will stop on a consonant on the next spin, we need to add up the frequencies of outcomes K, N, and D (since I is a vowel).
Adding the frequencies:
140 (K) + 105 (N) + 135 (D) = 380
Now, find the probability of landing on a consonant by dividing the total frequency of consonants by the total number of spins:
380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76.
Use the table to answer the question.
Outcomes K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K , I , N , D . Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?
(1 point)
Responses
0.24
0.24
0.45
0.45
0.72
0.72
0.28
7 answers
so what's the answer
Apologies for the previous miscalculation. Let's recalculate the probability:
Consonants: K, N, D
Total frequency of consonants: 140 + 105 + 135 = 380
Total number of spins: 500
Probability of landing on a consonant = Frequency of consonants / Total spins = 380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76.
Consonants: K, N, D
Total frequency of consonants: 140 + 105 + 135 = 380
Total number of spins: 500
Probability of landing on a consonant = Frequency of consonants / Total spins = 380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76.
wong
My apologies for the errors in my previous responses. Let's correct it.
Total frequency of consonants (K, N, D) = 140 + 105 + 135 = 380
Total frequency of all outcomes = 120 + 140 + 105 + 135= 500
Probability of landing on a consonant = Frequency of consonants / Total frequency = 380 / 500 = 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76 or 76%.
Total frequency of consonants (K, N, D) = 140 + 105 + 135 = 380
Total frequency of all outcomes = 120 + 140 + 105 + 135= 500
Probability of landing on a consonant = Frequency of consonants / Total frequency = 380 / 500 = 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76 or 76%.
there is no 76
I apologize for the errors in my previous responses. Let's correct it.
Total frequency of consonants (K, N, D) = 140 + 105 + 135 = 380
Total frequency of all outcomes = 120 + 140 + 105 + 135 = 500
Probability of landing on a consonant = Frequency of consonants / Total frequency = 380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76 or 76%.
Total frequency of consonants (K, N, D) = 140 + 105 + 135 = 380
Total frequency of all outcomes = 120 + 140 + 105 + 135 = 500
Probability of landing on a consonant = Frequency of consonants / Total frequency = 380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76 or 76%.
1 answer