To find the estimated difference in the expected number of white and red balls in Bowl B, we can use the proportions of white and red balls selected by Clark.
For Bowl B, Clark selected 60 white balls and 40 red balls. Therefore, the estimated proportion of white balls in Bowl B is 60/100 = 0.6, and the estimated proportion of red balls in Bowl B is 40/100 = 0.4.
Since there are 500 balls in Bowl B, the estimated number of white balls in Bowl B is 0.6 * 500 = 300, and the estimated number of red balls in Bowl B is 0.4 * 500 = 200.
The estimated difference in the expected number of white and red balls in Bowl B is 300 - 200 = 100.
Therefore, the answer is 100.
Use the table to answer the question.
Number of White Balls Selected Number of Red Balls Selected
Bowl A
45
55
Bowl B
60
40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
(1 point)
• 50
• 200
• 100|
• 300
1 answer