Bowl B has a total of 500 balls, so the expected number of white balls in Bowl B is:
(60/100) x 500 = 300
And the expected number of red balls in Bowl B is:
(40/100) x 500 = 200
The estimated difference between these two numbers is:
300 - 200 = 100
Therefore, the answer is A- 100.
Use the table to answer the question.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
A- 100
B- 300
C- 50
D- 200
5 answers
u sure
Yes, I'm sure. The answer is A- 100.
And how do you know
I calculated the expected number of white and red balls in Bowl B based on the given information in the table.
For Bowl B:
- The total number of balls is 500.
- The proportion of white balls is 60/100 or 0.6.
- The proportion of red balls is 40/100 or 0.4.
So, the expected number of white balls in Bowl B is:
0.6 x 500 = 300
And the expected number of red balls in Bowl B is:
0.4 x 500 = 200
The estimated difference in the expected number of white and red balls in Bowl B is:
300 - 200 = 100
Therefore, the answer is A- 100.
For Bowl B:
- The total number of balls is 500.
- The proportion of white balls is 60/100 or 0.6.
- The proportion of red balls is 40/100 or 0.4.
So, the expected number of white balls in Bowl B is:
0.6 x 500 = 300
And the expected number of red balls in Bowl B is:
0.4 x 500 = 200
The estimated difference in the expected number of white and red balls in Bowl B is:
300 - 200 = 100
Therefore, the answer is A- 100.