Use the table to answer the question.
Number of Siblings: 0, 1, 2, 3, 4, 5 Number of 6th Graders: 3, 12, 5, 2, 0, 1
Kaylen wants to know how many siblings 6th graders have. She surveys the 6th graders on her soccer team. Her results are given in the table. She calculates that the interquartile range for number of siblings is 1. She then realizes that she counted one data value twice by accident. She needs to remove one of the “0 siblings” values from the table. Determine how removing a “0” from the dataset will impact the interquartile range.
A. The new interquartile range is 1. The interquartile range stayed the same.
B. The new interquartile range is 0.5. The interquartile range decreased.
C. The new interquartile range is 1.5. The interquartile range increased.
D. The new interquartile range is 6.5. The interquartile range increased.
11 answers
Removing one of the "0 siblings" values from the dataset will not change the interquartile range, as the interquartile range is based on the middle 50% of the data and is not affected by extreme values at the edges of the dataset. Therefore, the correct answer is:
A. The new interquartile range is 1. The interquartile range stayed the same.
{$35.80,$79.60,$38.10,$20.50,$10.45,$96.78,$45.90}
After Yasmine creates the dataset, she works an additional night and earns $98.20 in tips. Determine the range of the original dataset and the range of the new dataset with the new data point of $98.20 added.
A. The range of the original dataset is $10.10, and the range of the new dataset is $62.40.
B. The range of the original dataset is $86.33, and the range of the new dataset is $87.75.
C. The range of the original dataset is $35.45, and the range of the new dataset is $87.75.
D. The range of the original dataset is $10.10, and the range of the new dataset is also $10.10.
Original dataset: {$35.80, $79.60, $38.10, $20.50, $10.45, $96.78, $45.90}
Largest value: $96.78
Smallest value: $10.45
Range of the original dataset = $96.78 - $10.45 = $86.33
New dataset with the additional data point: {$35.80, $79.60, $38.10, $20.50, $10.45, $96.78, $45.90, $98.20}
Largest value: $98.20
Smallest value: $10.45
Range of the new dataset = $98.20 - $10.45 = $87.75
Therefore, the correct answer is:
B. The range of the original dataset is $86.33, and the range of the new dataset is $87.75.
Original dataset: {$35.80, $79.60, $38.10, $20.50, $10.45, $96.78, $45.90}
Largest value: $96.78
Smallest value: $10.45
Range of the original dataset = $96.78 - $10.45 = $86.33
New dataset with the additional data point: {$35.80, $79.60, $38.10, $20.50, $10.45, $96.78, $45.90, $98.20}
Largest value: $98.20
Smallest value: $10.45
Range of the new dataset = $98.20 - $10.45 = $87.75
Therefore, the correct answer is:
B. The range of the original dataset is $86.33, and the range of the new dataset is $87.75.
its a arrow from 4 to 12 and between 7.5 and 8 there is a box and between 8.5 to 10.5 there is another box
From the box plot you described:
- The lower fence represents the minimum value, which is 4 (at the beginning of the plot).
- The minimum value of the dataset is also represented by the lower whisker.
- The upper fence represents the maximum value, which is 12 (at the end of the plot).
- The maximum value of the dataset is also represented by the upper whisker.
The range of the dataset is the difference between the maximum and minimum values:
Range = Maximum Value - Minimum Value
Range = 12 - 4
Range = 8
Therefore, the range of the dataset based on the information from the box plot is 8.