To find the probability that the number of cube rolls is 6 given that the coin flip lands on heads, we can use the formula for conditional probability:
\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]
Where:
- \( A \) is the event that there are 6 cube rolls.
- \( B \) is the event that the coin lands on heads.
From the table, we can see:
- The number of times the coin lands on heads (event \( B \)) is 59.
- The number of times the coin lands on heads and there are 6 cube rolls (event \( A \cap B \)) is 6.
Hence, we can calculate the conditional probability \( P(A|B) \):
\[ P(A|B) = \frac{\text{Number of heads and 6 cube rolls}}{\text{Total number of heads}} = \frac{6}{59} \]
So the probability that the number of cube rolls is 6 given that the coin shows heads is:
\[ \frac{6}{59} \]
Thus, the correct response is:
\[ \text{Start Fraction 6 over 59 End Fraction} \]