Use the table to answer the question.

Minutes 1 8 15
Math Problems x 48 y
Jesse can complete 48 math problems in 8 minutes. How many math problems can she complete in 1 minute? How many math problems can she complete in 15 minutes?

(1 point)
Responses

9; 23
9; 23

7; 22
7; 22

6; 90
6; 90

24; 72
24; 72
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9 answers

To determine how many math problems Jesse can complete in 1 minute and 15 minutes, we can use the information given.

Jesse completes 48 math problems in 8 minutes.

First, we calculate how many problems she completes in 1 minute:

\[ \text{Problems per minute} = \frac{48 \text{ problems}}{8 \text{ minutes}} = 6 \text{ problems per minute} \]

Now, to find out how many problems she can complete in 15 minutes, we multiply the problems completed per minute by the number of minutes:

\[ \text{Problems in 15 minutes} = 6 \text{ problems per minute} \times 15 \text{ minutes} = 90 \text{ problems} \]

So, Jesse can complete 6 math problems in 1 minute and 90 math problems in 15 minutes. The correct answer is:

6; 90

Use the table to answer the question.

White Blue
3 4
x 8
9 12
12 y
For every 4 blue crayons in a box, there are 3 white ones. How many white crayons are there if there are 8 blue ones? How many blue crayons are there if there are 12 white ones?

(1 point)
Responses

9; 12
9; 12

4; 8
4; 8

12; 16
12; 16

6; 16
6; 16
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page 8 of 8

The problem states that for every 4 blue crayons, there are 3 white crayons. We can set up a ratio based on that information:

\[ \text{White : Blue} = 3 : 4 \]

1. Finding the number of white crayons when there are 8 blue crayons:

We know that if there are 4 blue crayons, there are 3 white crayons. To find out how many white crayons correspond to 8 blue crayons, we can set up the proportions:

\[ \frac{3 \text{ white}}{4 \text{ blue}} = \frac{x \text{ white}}{8 \text{ blue}} \]

Cross-multiplying gives:

\[ 3 \times 8 = 4 \times x \] \[ 24 = 4x \] \[ x = 6 \]

So, when there are 8 blue crayons, there are 6 white crayons.

2. Finding the number of blue crayons when there are 12 white crayons:

Again using the ratio:

\[ \frac{3 \text{ white}}{4 \text{ blue}} = \frac{12 \text{ white}}{y \text{ blue}} \]

Cross-multiplying gives:

\[ 3y = 4 \times 12 \] \[ 3y = 48 \] \[ y = 16 \]

So, when there are 12 white crayons, there are 16 blue crayons.

The answers are: 6; 16.

None of the provided responses exactly match this pair. Please verify if there might be additional context or an alternate interpretation of the ratios involved.

Use the table to answer the question.

8 48
10 60
x 72
y 84Analyze the ratios in the table to find the missing values.(1 point)
Responses

18; 26
18; 26

432; 504
432; 504

12; 14
12; 14

22; 34

To analyze the ratios in the table, let's first identify the pattern in the provided values.

The table looks like this:

| First Value | Second Value | |------------------|------------------| | 8 | 48 | | 10 | 60 | | x | 72 | | y | 84 |

Finding the ratio:

  1. Calculate the ratio of the first and second values in the first two rows:

    • For the first row: \[ \frac{48}{8} = 6 \]

    • For the second row: \[ \frac{60}{10} = 6 \]

    The ratio appears to be consistent at \( \frac{\text{Second Value}}{\text{First Value}} = 6 \).

Finding \( x \) when the second value is 72:

We use the same ratio to find \( x \): \[ \frac{72}{x} = 6 \]

Cross-multiply to solve for \( x \): \[ 72 = 6x \] \[ x = \frac{72}{6} = 12 \]

Finding \( y \) when the second value is 84:

Now, we can find \( y \) using the same ratio: \[ \frac{84}{y} = 6 \]

Again, cross-multiply to solve for \( y \): \[ 84 = 6y \] \[ y = \frac{84}{6} = 14 \]

Conclusion:

Thus, the missing values are \( x = 12 \) and \( y = 14 \).

The correct response is 12; 14.

You're welcome! If you have any more questions or need further assistance, feel free to ask. Happy studying!

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