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Original Question
Use the table to answer the question. Line Equation Line A y=2x−3 Line B y=2x+5 Line C y=−12x−2 Line D y=12x+2 Given the linear...Asked by smarty pants
Use the table to answer the question.
Line Equation
Line A y=2x−3
Line B y=2x+5
Line C y=−12x−2
Line D y=12x+2
Given the linear equations in the table, which of the following statements is true?
(1 point)
Responses
Line C is perpendicular to line D.
Line upper C is perpendicular to line upper D .
Line A is perpendicular to line C.
Line upper A is perpendicular to line upper C .
Line A is perpendicular to line B.
Line upper A is perpendicular to line upper B .
Line B is perpendicular to line D.
Line Equation
Line A y=2x−3
Line B y=2x+5
Line C y=−12x−2
Line D y=12x+2
Given the linear equations in the table, which of the following statements is true?
(1 point)
Responses
Line C is perpendicular to line D.
Line upper C is perpendicular to line upper D .
Line A is perpendicular to line C.
Line upper A is perpendicular to line upper C .
Line A is perpendicular to line B.
Line upper A is perpendicular to line upper B .
Line B is perpendicular to line D.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which lines are perpendicular, we need to look at the slopes of the lines given in their equations.
The standard form of a linear equation is \(y = mx + b\), where \(m\) is the slope.
From the equations provided:
- Line A: \(y = 2x - 3\) → slope \(m_A = 2\)
- Line B: \(y = 2x + 5\) → slope \(m_B = 2\)
- Line C: \(y = -12x - 2\) → slope \(m_C = -12\)
- Line D: \(y = 12x + 2\) → slope \(m_D = 12\)
Two lines are perpendicular if the product of their slopes is \(-1\) (i.e., \(m_1 \times m_2 = -1\)).
Now, let's analyze the pairs:
1. **Line C and Line D**:
- \(m_C \times m_D = -12 \times 12 = -144\) (not perpendicular)
2. **Line A and Line C**:
- \(m_A \times m_C = 2 \times -12 = -24\) (not perpendicular)
3. **Line A and Line B**:
- \(m_A \times m_B = 2 \times 2 = 4\) (not perpendicular)
4. **Line B and Line D**:
- \(m_B \times m_D = 2 \times 12 = 24\) (not perpendicular)
None of the given lines are perpendicular to each other since none of the products of their slopes equals \(-1\).
Based on the original statements provided, all of them would be false. Therefore, none of the selected relations between the lines accurately represents perpendicularity.
The standard form of a linear equation is \(y = mx + b\), where \(m\) is the slope.
From the equations provided:
- Line A: \(y = 2x - 3\) → slope \(m_A = 2\)
- Line B: \(y = 2x + 5\) → slope \(m_B = 2\)
- Line C: \(y = -12x - 2\) → slope \(m_C = -12\)
- Line D: \(y = 12x + 2\) → slope \(m_D = 12\)
Two lines are perpendicular if the product of their slopes is \(-1\) (i.e., \(m_1 \times m_2 = -1\)).
Now, let's analyze the pairs:
1. **Line C and Line D**:
- \(m_C \times m_D = -12 \times 12 = -144\) (not perpendicular)
2. **Line A and Line C**:
- \(m_A \times m_C = 2 \times -12 = -24\) (not perpendicular)
3. **Line A and Line B**:
- \(m_A \times m_B = 2 \times 2 = 4\) (not perpendicular)
4. **Line B and Line D**:
- \(m_B \times m_D = 2 \times 12 = 24\) (not perpendicular)
None of the given lines are perpendicular to each other since none of the products of their slopes equals \(-1\).
Based on the original statements provided, all of them would be false. Therefore, none of the selected relations between the lines accurately represents perpendicularity.
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