To solve the quadratic equation \((x-7)^2 = 11\), we first need to find the solutions by taking the square root of both sides. Here are the steps:
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Rewrite the equation: \[ (x-7)^2 = 11 \]
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Take the square root of both sides: \[ x - 7 = \pm \sqrt{11} \]
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Solve for \(x\): \[ x = 7 + \sqrt{11} \quad \text{and} \quad x = 7 - \sqrt{11} \]
Now we'll compute the numeric values of each solution.
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For \(x = 7 + \sqrt{11}\):
- \(\sqrt{11} \approx 3.317\) (approximately)
- Thus, \(x \approx 7 + 3.317 = 10.317\)
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For \(x = 7 - \sqrt{11}\):
- Thus, \(x \approx 7 - 3.317 = 3.683\)
Now we can state the two solutions:
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The smaller solution is: \[ x \approx 3.683 \]
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The larger solution is: \[ x \approx 10.317 \]
In conclusion:
- The smaller of the two solutions is \(x = 7 - \sqrt{11} \approx 3.683\).
- The larger of the two solutions is \(x = 7 + \sqrt{11} \approx 10.317\).
Final answers:
- The smaller of the two solutions is \(x = 7 - \sqrt{11} \approx 3.683\).
- The larger of the two solutions is \(x = 7 + \sqrt{11} \approx 10.317\).