Use the table to answer the question.
Dog Breed
Height
Weight
Length
Dachshund
8 in.
12 lb.
14 in.
Basset Hound
12 in.
40 lb.
24 in.
Great Dane
40 in.
150 lb.
45 in.
Kyle includes this table in their report on the dogs they walk. They want to add another example of categorical data. Which of the following options would be suitable?
(1 point)
amount of food per day
number of teeth
age
color
11 answers
Color
Review the two-way frequency table. What are the missing values? (1 point)
Favorite Snack
Third Graders
Fourth Graders
Total
Salty
35
43
Sweet
42
57
Total
50
50
100
Favorite Snack
Third Graders
Fourth Graders
Total
Salty
35
43
Sweet
42
57
Total
50
50
100
To find the missing values, we need to subtract the given values from the total values for each category.
For Third Graders:
Total Third Graders = Total - Fourth Graders = 50 - 50 = 0
The missing value for Third Graders who like Salty snacks is 0.
For Fourth Graders:
Total Fourth Graders = Total - Third Graders = 50 - 50 = 0
The missing value for Fourth Graders who like Salty snacks is 0.
For Third Graders:
Total Third Graders = Total - Fourth Graders = 50 - 50 = 0
The missing value for Third Graders who like Salty snacks is 0.
For Fourth Graders:
Total Fourth Graders = Total - Third Graders = 50 - 50 = 0
The missing value for Fourth Graders who like Salty snacks is 0.
Use the table to answer the question.
Plays winter sports
Does not play winter sports
Colorado
103
35
138
Nebraska
54
95
149
Total
157
130
Totals
287
Based on the two-way frequency table, what is the marginal relative frequency of people who play winter sports? Round your answer to the nearest whole percentage.
(1 point)
percent
Plays winter sports
Does not play winter sports
Colorado
103
35
138
Nebraska
54
95
149
Total
157
130
Totals
287
Based on the two-way frequency table, what is the marginal relative frequency of people who play winter sports? Round your answer to the nearest whole percentage.
(1 point)
percent
To find the marginal relative frequency of people who play winter sports, we need to divide the total number of people who play winter sports by the total number of people.
Total number of people who play winter sports: 157
Total number of people: 287
Marginal relative frequency = (Number of people who play winter sports / Total number of people) * 100
Marginal relative frequency = (157 / 287) * 100 ≈ 54.7%
Therefore, the marginal relative frequency of people who play winter sports is approximately 55%.
Total number of people who play winter sports: 157
Total number of people: 287
Marginal relative frequency = (Number of people who play winter sports / Total number of people) * 100
Marginal relative frequency = (157 / 287) * 100 ≈ 54.7%
Therefore, the marginal relative frequency of people who play winter sports is approximately 55%.
Use the table to answer the question.
Sprinkles
Jelly Beans
Total
Vanilla
102
73
175
Chocolate
65
125
190
Total
167
198
365
You have gathered your grade's votes for favorite ice cream flavor and topping. Then you organized the data into a two-way frequency table. Interpret the table to generate a two-way table of conditional relative frequencies for students who prefer sprinkles or jelly beans, given they prefer chocolate or vanilla. Round your answers to the nearest whole percentage.
(1 point)
Sprinkles (%)
Jelly Beans (%)
Vanilla
Chocolate
%
34
%
66
Sprinkles
Jelly Beans
Total
Vanilla
102
73
175
Chocolate
65
125
190
Total
167
198
365
You have gathered your grade's votes for favorite ice cream flavor and topping. Then you organized the data into a two-way frequency table. Interpret the table to generate a two-way table of conditional relative frequencies for students who prefer sprinkles or jelly beans, given they prefer chocolate or vanilla. Round your answers to the nearest whole percentage.
(1 point)
Sprinkles (%)
Jelly Beans (%)
Vanilla
Chocolate
%
34
%
66
To find the conditional relative frequencies, we need to calculate the percentages for students who prefer Sprinkles or Jelly Beans given they prefer Chocolate or Vanilla.
For Vanilla:
- Students who prefer Sprinkles and Vanilla: 102
- Students who prefer Jelly Beans and Vanilla: 73
Total for Vanilla: 175
Conditional relative frequency of Sprinkles (given Vanilla): (Students who prefer Sprinkles and Vanilla / Total for Vanilla) * 100
= (102 / 175) * 100 ≈ 58.3%
Conditional relative frequency of Jelly Beans (given Vanilla): (Students who prefer Jelly Beans and Vanilla / Total for Vanilla) * 100
= (73 / 175) * 100 ≈ 41.7%
For Chocolate:
- Students who prefer Sprinkles and Chocolate: 65
- Students who prefer Jelly Beans and Chocolate: 125
Total for Chocolate: 190
Conditional relative frequency of Sprinkles (given Chocolate): (Students who prefer Sprinkles and Chocolate / Total for Chocolate) * 100
= (65 / 190) * 100 ≈ 34.2%
Conditional relative frequency of Jelly Beans (given Chocolate): (Students who prefer Jelly Beans and Chocolate / Total for Chocolate) * 100
= (125 / 190) * 100 ≈ 65.8%
Therefore, the two-way table of conditional relative frequencies for students who prefer sprinkles or jelly beans, given they prefer chocolate or vanilla, would be as follows:
Sprinkles (%):
- Given Vanilla: 58%
- Given Chocolate: 34%
Jelly Beans (%):
- Given Vanilla: 42%
- Given Chocolate: 66%
For Vanilla:
- Students who prefer Sprinkles and Vanilla: 102
- Students who prefer Jelly Beans and Vanilla: 73
Total for Vanilla: 175
Conditional relative frequency of Sprinkles (given Vanilla): (Students who prefer Sprinkles and Vanilla / Total for Vanilla) * 100
= (102 / 175) * 100 ≈ 58.3%
Conditional relative frequency of Jelly Beans (given Vanilla): (Students who prefer Jelly Beans and Vanilla / Total for Vanilla) * 100
= (73 / 175) * 100 ≈ 41.7%
For Chocolate:
- Students who prefer Sprinkles and Chocolate: 65
- Students who prefer Jelly Beans and Chocolate: 125
Total for Chocolate: 190
Conditional relative frequency of Sprinkles (given Chocolate): (Students who prefer Sprinkles and Chocolate / Total for Chocolate) * 100
= (65 / 190) * 100 ≈ 34.2%
Conditional relative frequency of Jelly Beans (given Chocolate): (Students who prefer Jelly Beans and Chocolate / Total for Chocolate) * 100
= (125 / 190) * 100 ≈ 65.8%
Therefore, the two-way table of conditional relative frequencies for students who prefer sprinkles or jelly beans, given they prefer chocolate or vanilla, would be as follows:
Sprinkles (%):
- Given Vanilla: 58%
- Given Chocolate: 34%
Jelly Beans (%):
- Given Vanilla: 42%
- Given Chocolate: 66%
Use the table to answer the question.
GPA Above 3.0 GPA Below 3.0
Involved in Extracurricular Activities
Not Involved in Extracurricular Activities
68
Total
12
80
22
38
60
Total
(1 point)
90
50
140
A group of ninth-grade math teachers collected the data in the table about the grades of students who are involved in extracurricular activities compared to the grades of students who are not involved in extracurricular activities. What percentage of students who are involved in extracurricular activities have a GPA above 3.0?
Of the students that are involved in extracurricular activities, % have a GPA above 3.0.
GPA Above 3.0 GPA Below 3.0
Involved in Extracurricular Activities
Not Involved in Extracurricular Activities
68
Total
12
80
22
38
60
Total
(1 point)
90
50
140
A group of ninth-grade math teachers collected the data in the table about the grades of students who are involved in extracurricular activities compared to the grades of students who are not involved in extracurricular activities. What percentage of students who are involved in extracurricular activities have a GPA above 3.0?
Of the students that are involved in extracurricular activities, % have a GPA above 3.0.
To find the percentage of students who are involved in extracurricular activities and have a GPA above 3.0, we need to calculate the proportion of students in that category and then convert it to a percentage.
From the table:
- Number of students involved in extracurricular activities and have a GPA above 3.0: 68
- Total number of students involved in extracurricular activities: 60
Percentage of students who are involved in extracurricular activities and have a GPA above 3.0: (Number of students with GPA above 3.0 / Total students involved in extracurricular activities) * 100
= (68 / 60) * 100
≈ 113.33%
Therefore, of the students who are involved in extracurricular activities, approximately 113.33% have a GPA above 3.0.
From the table:
- Number of students involved in extracurricular activities and have a GPA above 3.0: 68
- Total number of students involved in extracurricular activities: 60
Percentage of students who are involved in extracurricular activities and have a GPA above 3.0: (Number of students with GPA above 3.0 / Total students involved in extracurricular activities) * 100
= (68 / 60) * 100
≈ 113.33%
Therefore, of the students who are involved in extracurricular activities, approximately 113.33% have a GPA above 3.0.
Use the table to answer the question.
X
y
-53
-44
-37
-2 7.5
-1 2.5
Use a spreadsheet calculator to determine the least squares regression line for the points in table. Round to the nearest hundredth if necessary.
(1 point)
y = 5.55x - 0.25
y = 0.25x - 5.55
y = 5.55x + 0.25
y = 0.25x + 5.55
X
y
-53
-44
-37
-2 7.5
-1 2.5
Use a spreadsheet calculator to determine the least squares regression line for the points in table. Round to the nearest hundredth if necessary.
(1 point)
y = 5.55x - 0.25
y = 0.25x - 5.55
y = 5.55x + 0.25
y = 0.25x + 5.55
To find the least squares regression line for the given points in the table, we can use a spreadsheet calculator or a statistical software like Excel. By calculating the regression, we can determine the coefficients of the line.
Using the provided points (-53, -44), (-37, -27.5), and (-1, 2.5), the least squares regression line is determined to be:
y = 0.25x + 5.55
Therefore, the correct option is:
y = 0.25x + 5.55
Using the provided points (-53, -44), (-37, -27.5), and (-1, 2.5), the least squares regression line is determined to be:
y = 0.25x + 5.55
Therefore, the correct option is:
y = 0.25x + 5.55
1 answer