To compare the functions \( f(x) \) and \( g(x) \) based on the provided table:
- For \( x = -2 \): \( f(-2) = -1 \) and \( g(-2) = -1 \) (intersection)
- For \( x = -1 \): \( f(-1) = \frac{3}{4} \) and \( g(-1) = 0 \) ( \( f(-1) > g(-1) \))
- For \( x = 0 \): \( f(0) = 1 \) and \( g(0) = 1 \) (intersection)
- For \( x = 1 \): \( f(1) = 1 \frac{1}{4} = \frac{5}{4} \) and \( g(1) = 2 \) ( \( f(1) < g(1) \))
- For \( x = 2 \): \( f(2) = 3 \) and \( g(2) = 3 \) (intersection)
Intersection Points:
- The functions intersect at \( x = -2 \), \( x = 0 \), and \( x = 2 \). So there are 3 points of intersection.
When is \( f(x) \) greater than or equal to \( g(x) \)?
From the values analyzed:
- \( f(x) \) is greater than or equal to \( g(x) \) when:
- For \( x < -1 \): \( f(-2) = g(-2) \) (equal)
- Between \( -1 < x < 1 \): \( f(x) > g(x) \)
Thus, the range where \( f(x) \) is greater than or equal to \( g(x) \) is:
- \( -2 \leq x < 1 \)
Final Answers:
- The functions intersect at 3 points.
- \( f(x) \) is greater than or equal to \( g(x) \) when \( -2 \leq x < 1 \).