Use the table of the masses of several objects to answer the question.

Object Mass (grams)
paper clip 1.0
penny 2.5
book 860
cereal box 500
small pot 1,200
Between which two objects is gravitational attraction the greatest if placed 1 meter apart?

(1 point)
Responses

between the paper clip and the penny
between the paper clip and the penny

between the penny and the small pot
between the penny and the small pot

between the book and the cereal box
between the book and the cereal box

between the small pot and the book

1 answer

To determine which two objects have the greatest gravitational attraction when placed 1 meter apart, we can use the formula for gravitational force:

\[ F = G \frac{m_1 m_2}{r^2} \]

where:

  • \( F \) is the gravitational force,
  • \( G \) is the gravitational constant,
  • \( m_1 \) and \( m_2 \) are the masses of the two objects,
  • \( r \) is the distance between the objects (which is constant at 1 meter for our comparison).

Since \( G \) and \( r^2 \) are constant in this scenario, we can simplify the comparison to just the product of the masses \( m_1 \) and \( m_2 \).

Let's calculate the products of the masses for each pair of objects:

  1. Paper clip (1.0 g) and Penny (2.5 g): \[ 1.0 \times 2.5 = 2.5 \]

  2. Penny (2.5 g) and Small pot (1,200 g): \[ 2.5 \times 1,200 = 3,000 \]

  3. Book (860 g) and Cereal box (500 g): \[ 860 \times 500 = 430,000 \]

  4. Small pot (1,200 g) and Book (860 g): \[ 1,200 \times 860 = 1,032,000 \]

Now, let's compare these products:

  • Between paper clip and penny: \( 2.5 \)
  • Between penny and small pot: \( 3,000 \)
  • Between book and cereal box: \( 430,000 \)
  • Between small pot and book: \( 1,032,000 \)

Thus, the greatest gravitational attraction occurs between the small pot and the book.