molar mass C2H5OH = 2*12.01 + 6*1.01 + 1*16 = 46.08 g/mol
30 g C2H5OH x (1 mol/46.08 g) = ? moles C2H5OH.
Use the table of molar masses to complete the activity.
Element Molar Mass(g/mol)
Carbon 12.01
Hydrogen 1.01
Oxygen 16.00
A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In one to two sentences, make and justify a claim about the number of moles of ethanol the chemist will use.
4 answers
CH3CH2OHg/mol=2*12.01+6*1.01+16=46.08g/mol
30/46.08=0.651mol.
30/46.08=0.651mol.
So what is the justification or claim the chemist will use…The question is “A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In one to two sentences, make and justify a claim about the number of moles of ethanol the chemist will use?”. Do anyone know the correct answer? Please help!
The answer is :
The the chemist will use a number 0.65 moles of ethanol.
The the chemist will use a number 0.65 moles of ethanol.