Let x^2 = u ; 2x dx = du
The integral becomes (using a Table of Integrals):
(1/2) integral of sin(6u)*cos(7u)
= (1/4)[sin(u)- cos(13u/13]
= (1/4)[sin(x^2) - cos(13x^2)/13]
Use the Table of Integrals to evaluate the integral (x sine(6x^2)cos(7x^2)dx)
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