To compare the kinetic and potential energies of the two watermelons, we can use the formulas for each type of energy.
Kinetic Energy (KE) is given by the formula: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is mass and \( v \) is speed.
Potential Energy (PE) in this context is dependent on height (which is not provided in the table), but it can be assumed the watermelons start from the same height, resulting in the same potential energy for both.
Calculating Kinetic Energy for each watermelon:
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Watermelon A: \[ KE_A = \frac{1}{2} \times 4 , \text{kg} \times (2 , \text{m/s})^2 \] \[ KE_A = \frac{1}{2} \times 4 \times 4 \] \[ KE_A = \frac{1}{2} \times 16 = 8 , \text{J} \]
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Watermelon B: \[ KE_B = \frac{1}{2} \times 4 , \text{kg} \times (4 , \text{m/s})^2 \] \[ KE_B = \frac{1}{2} \times 4 \times 16 \] \[ KE_B = \frac{1}{2} \times 64 = 32 , \text{J} \]
Now to compare:
- Kinetic Energy:
- Watermelon A: 8 J
- Watermelon B: 32 J
Watermelon B has more kinetic energy.
- Potential Energy: Since both watermelons are assumed to be at the same height, they have the same potential energy assuming they are dropped from the same height.
Conclusion: Watermelon B has more kinetic energy than Watermelon A, while both have the same potential energy.
So the correct response is: The watermelon B has more kinetic energy.