To compare the kinetic energies of the two watermelons, we can use the formula for kinetic energy (KE):
\[ KE = \frac{1}{2}mv^2 \]
Where \(m\) is the mass and \(v\) is the speed.
For Watermelon A:
- Mass \(m = 4 , \text{kg}\)
- Speed \(v = 2 , \text{m/s}\)
Calculating kinetic energy for Watermelon A:
\[ KE_A = \frac{1}{2} \times 4 \times (2)^2 = \frac{1}{2} \times 4 \times 4 = \frac{1}{2} \times 16 = 8 , \text{J} \]
For Watermelon B:
- Mass \(m = 4 , \text{kg}\)
- Speed \(v = 4 , \text{m/s}\)
Calculating kinetic energy for Watermelon B:
\[ KE_B = \frac{1}{2} \times 4 \times (4)^2 = \frac{1}{2} \times 4 \times 16 = \frac{1}{2} \times 64 = 32 , \text{J} \]
Comparison of kinetic energies:
- Watermelon A: \(8 , \text{J}\)
- Watermelon B: \(32 , \text{J}\)
Thus, Watermelon B has more kinetic energy.
Regarding potential energy, if both watermelons are falling from the same height, their potential energy at that height will be the same since potential energy (PE) is calculated by:
\[ PE = mgh \]
Where \(h\) is the height from which they are falling (assuming it's the same for both).
In conclusion, based on the calculations:
The watermelon B has more kinetic energy.