To compare the kinetic energies of the two watermelons, we can use the formula for kinetic energy:
\[ KE = \frac{1}{2}mv^2 \]
where \( m \) is the mass and \( v \) is the speed.
For Watermelon A:
- Mass \( m_A = 4 \) kg
- Speed \( v_A = 2 \) m/s
\[ KE_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 , \text{J} \]
For Watermelon B:
- Mass \( m_B = 4 \) kg
- Speed \( v_B = 4 \) m/s
\[ KE_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 , \text{J} \]
Now we can compare the kinetic energies:
- \( KE_A = 8 , \text{J} \)
- \( KE_B = 32 , \text{J} \)
Watermelon B has more kinetic energy than Watermelon A.
So the correct response is:
The watermelon B has more kinetic energy.