To compare the kinetic energies of Watermelon A and Watermelon B, we can use the formula for kinetic energy:
\[ KE = \frac{1}{2} m v^2 \]
Where:
- \( KE \) is the kinetic energy,
- \( m \) is the mass of the fruit,
- \( v \) is the speed of the fruit.
For Watermelon A:
- Mass \( m = 4 \) kg
- Speed \( v = 2 \) m/s
\[ KE_A = \frac{1}{2} (4) (2^2) = \frac{1}{2} (4) (4) = 8 \text{ J} \]
For Watermelon B:
- Mass \( m = 4 \) kg
- Speed \( v = 4 \) m/s
\[ KE_B = \frac{1}{2} (4) (4^2) = \frac{1}{2} (4) (16) = 32 \text{ J} \]
Now comparing the kinetic energies:
- Kinetic energy of Watermelon A: 8 J
- Kinetic energy of Watermelon B: 32 J
Thus, Watermelon B has more kinetic energy.
Regarding potential energy, both watermelons are falling from the same height (the counter), which means they have the same potential energy just before they fall, but as they fall, their potential energy decreases while their kinetic energy increases.
Therefore, the correct response is:
The watermelon B has more kinetic energy.