Use the Substitution method to solve the system of equations.

Question

y - 2x = -5
3y - x = 5

Solve the first equation for y.
y = 2x-5
Substitute that for y in the second equation and solve for x. Then use the value of x to substitute back into the first equation and solve for y. Post your work if you get stuck.

WOULD IT BE:
4Y-X=0?

y - 2x = -5 (equation 1)
3y - x = 5 (equation 2)
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Use equation 1 to solve for y as I did earlier.
y = 2x + 5
Now substitute that value of y (from equation 1) into equation 2.
equation 2 is
3y-x=5. Plug the value for y into this.
3(2x+5)-x=5
Now solve for x. Then use that value for x into equation 1 and solve for y.
Post your work if you get stuck. Not a "would it be" answer.

what is a possible point that lies on the graph

y=-2x-5

yo mama

Answer 1

well. im failing algebra jus as u r probably if ur askin help online from random ppl. sorry i cant help.

Answer 2

Wrong

Answer 3

Lesson 3: Review of Solving Equations
Algebra 1 B unit 1: Mia-Year Refresher

B
A
D
A
C

Answer 4

Anonymous is right! I got 100%! Thank u!

Answer 5

Solve the equation.

–3 + x = 11
A. –8
B. –14
C. 8
D. 14

Answer 6

Add 3 to both sides:

-3 + x + 3 = 11 + 3

Simplify:

x = 14

Answer: D) 14

Answer 7

Solve the equation.

Q – 21 = –52

Answer 8

Solve the equation.

Q – 21 = –52
A. –31
B. –73
C. 31
D. 73

Answer 9

Add 21 to both sides of the equation:

Q - 21 + 21 = -52 + 21

Simplify:

Q = -31

Answer: A) -31