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Use the substituion method to solve the system y = -3, y = 2x + 1.

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To solve the system of equations using the substitution method, we have:

  1. \( y = -3 \)
  2. \( y = 2x + 1 \)

Since \( y \) is already expressed in the first equation, we can substitute \(-3\) for \( y \) in the second equation.

Now, substitute \( y \) in the second equation:

\[ -3 = 2x + 1 \]

Next, solve for \( x \):

  1. Subtract 1 from both sides: \[ -3 - 1 = 2x \] \[ -4 = 2x \]

  2. Divide both sides by 2: \[ x = -2 \]

Now that we have found \( x = -2 \), we can substitute this value back into the first equation to find \( y \):

\[ y = -3 \]

Thus, the solution to the system of equations is: \[ (x, y) = (-2, -3) \]

Final answer:

\[ (-2, -3) \]