Question

Use the standard algorithm to find the product of 246 and 188. Record the products of each multiplying through by each place value in 188 as well as the final product.(2 points) The product of multiplying by the ones digit is . The product of multiplying by the tens digit is . The product of multiplying by the hundreds digit is . The product is .

Answer 1

To find the product of 246 and 188 using the standard algorithm, we can break it down by multiplying 246 by each digit of 188, considering their place values:

1. Multiply by the ones digit (8): \[ 246 \times 8 = 1968 \]

2. Multiply by the tens digit (8), but it's actually 80 because it's the tens place: \[ 246 \times 8 \times 10 = 2460 \times 8 = 19680 \]

3. Multiply by the hundreds digit (1), but it's actually 100 because it's the hundreds place: \[ 246 \times 1 \times 100 = 24600 \]

Now, we'll write down the parts we found:

• The product of multiplying by the ones digit is: 1968
• The product of multiplying by the tens digit is: 19680
• The product of multiplying by the hundreds digit is: 24600

Now, we add these products together to find the final product:

\[ \begin{align*} & 1968 \ +& 19680 \ +& 24600 \ \hline & 46248 \ \end{align*} \]

The final product of multiplying 246 by 188 is: 46248.

So the complete entries are:

• The product of multiplying by the ones digit is 1968.
• The product of multiplying by the tens digit is 19680.
• The product of multiplying by the hundreds digit is 24600.
• The product is 46248.