Use the square root property to solve the equation.​(xplus4​)squaredequals4Question content area bottomPart 1The​ solution(s) is/are xequalsenter your response here.​(Simplify your​ answer, including any radicals. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as​ needed.)

Answer 1

To solve the equation \((x + 4)^2 = 4\) using the square root property, we can first take the square root of both sides. The square root property states that if \(a^2 = b\), then \(a = \sqrt{b}\) or \(a = -\sqrt{b}\).

1. Start with the equation: \[ (x + 4)^2 = 4 \]

2. Apply the square root property: \[ x + 4 = \sqrt{4} \quad \text{or} \quad x + 4 = -\sqrt{4} \]

3. Since \(\sqrt{4} = 2\), we have: \[ x + 4 = 2 \quad \text{or} \quad x + 4 = -2 \]

4. Solve each equation:

   • For \(x + 4 = 2\): \[ x = 2 - 4 \implies x = -2 \]

   • For \(x + 4 = -2\): \[ x = -2 - 4 \implies x = -6 \]

Thus, the solutions are: \[ x = -2, -6 \]

In conclusion, the solution(s) is/are: \[ \boxed{-2, -6} \]