Use the special triangles on the unit circle to determine θ in degrees when sinθ=3√2 . (1 point) Responses 30° 30° 90° 90° 60° 60° 45°

Answer 1

The sine function has a maximum value of 1 for any angle. Therefore, there are no angles \( \theta \) for which \( \sin \theta = \frac{3\sqrt{2}}{2} \) because \( \frac{3\sqrt{2}}{2} \) is greater than 1.

Thus, there is no corresponding angle \( \theta \) for \( \sin \theta = \frac{3\sqrt{2}}{2} \) in the given responses (30°, 60°, 45°, or 90°). The sine values range only from -1 to 1.

Hence, there is no valid solution for \( \theta \) in this case.