To solve \(-2 \frac{1}{2} + 6 \frac{2}{3}\), we will follow these steps:
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Convert mixed numbers to improper fractions.
For \(-2 \frac{1}{2}\): \[ -2 \frac{1}{2} = -\left(2 \times 2 + 1\right)/2 = -\frac{5}{2} \]
For \(6 \frac{2}{3}\): \[ 6 \frac{2}{3} = 6 \times 3 + 2/3 = \frac{20}{3} \]
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Find a common denominator.
The denominators are 2 and 3. The least common denominator (LCD) is 6.
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Convert fractions to have the same denominator.
Convert \(-\frac{5}{2}\) to sixths: \[ -\frac{5}{2} \times \frac{3}{3} = -\frac{15}{6} \]
Convert \(\frac{20}{3}\) to sixths: \[ \frac{20}{3} \times \frac{2}{2} = \frac{40}{6} \]
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Add the fractions.
Now, add \(-\frac{15}{6}\) and \(\frac{40}{6}\): \[ -\frac{15}{6} + \frac{40}{6} = \frac{-15 + 40}{6} = \frac{25}{6} \]
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Convert back to a mixed number.
Divide 25 by 6: \[ 25 \div 6 = 4 \quad \text{(remainder 1)} \] So, \(\frac{25}{6} = 4 \frac{1}{6}\).
Thus, the answer is:
4 and 1 sixth (or written as \(4 \frac{1}{6}\)).