use the remainder theorem to find the remainder when P(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3

Answer 1

Just plug in x = -3 and the value P(-3) is the remainder when P(x) is divided by (x+3).

Answer 2

-3[1 -9 -5 -3 4
-3 36 -93 288
1 -12 32 -96 292

x^3-12x^2+31x-96
x+3[x^4-9x^3-5x^2-3x+4
-(x^4+3x^3)
-12x^3-5x^2
-(-12x^3-36^2
31x^2-3x
(-31x^2+93x)
-96x+4
-(-96-288)
292

Answer 3

will the teacher know if i use lees ?

Answer 4

prolly,, just change it up a lil tho