Use the Remainder Theorem to find the remainder when P(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3.
How do I do this?
3 answers
use synthetic division
f(x)/(x-a) = f(a)
here a = -3
so we need f(-3)
f(-3) =(-3)^4-9(-3)^3-5(-3)^2-3(-3)+4
= 81 + 9*27 - 45 +9 + 4
= 81 + 243 - 45 + 9 + 4
here a = -3
so we need f(-3)
f(-3) =(-3)^4-9(-3)^3-5(-3)^2-3(-3)+4
= 81 + 9*27 - 45 +9 + 4
= 81 + 243 - 45 + 9 + 4
292 ?
2 answers