f(2) = 2(32) + 6(16) - 4 - 14 - 12 = 130
so c-2 is not a factor
by synthetic division, (hard to show in this format)
2 | 2 6 0 -1 -7 -12
....-------------
........4 20 40 78 142
....210 20 39 71 130
I guess I should have done the division first
Use the remainder theorem to find the remainder when f(x) is divided by x -2. Then use the factor theorem to determine whether x -2 is a factor of f(x)
f(x) = 2x^5 + 6x^4 - x^2 - 7x - 12
2 answers
Thank you!