Use the quotient rule to simplify the expression. Write the expression with positive exponents. Assume the variables represent nonzero real numbers.

StartFraction left parenthesis a plus 3 b right parenthesis squared Over left parenthesis a plus 3 b right parenthesis Superscript negative 6 EndFraction

1 answer

To simplify the expression

\[ \frac{(a + 3b)^2}{(a + 3b)^{-6}}, \]

we can use the properties of exponents. According to the quotient rule of exponents, when you divide two expressions with the same base, you subtract the exponents:

\[ \frac{x^m}{x^n} = x^{m - n}. \]

In our case, we have \( (a + 3b)^2 \) in the numerator and \( (a + 3b)^{-6} \) in the denominator. We can rewrite the expression applying the quotient rule:

\[ \frac{(a + 3b)^2}{(a + 3b)^{-6}} = (a + 3b)^{2 - (-6)} = (a + 3b)^{2 + 6} = (a + 3b)^{8}. \]

Since we want to express the final answer with positive exponents, we arrive at:

\[ (a + 3b)^8. \]

Therefore, the simplified expression is

\[ \boxed{(a + 3b)^8}. \]