Use the quotient property and negative exponent property to generate an equivalent expression for square root 49 over 7^-3. What will the rational exponent be for the new expression

The rational exponent for the new expression is __

1 answer

To find an equivalent expression for \(\frac{\sqrt{49}}{7^{-3}}\), we'll start by simplifying both the numerator and the denominator.

  1. Calculate the square root in the numerator: \[ \sqrt{49} = 7 \]

  2. Now, substitute this into the expression: \[ \frac{\sqrt{49}}{7^{-3}} = \frac{7}{7^{-3}} \]

  3. Use the quotient property of exponents, which states that \(\frac{a^m}{a^n} = a^{m-n}\):

    • Here, we have \(7^1\) in the numerator and \(7^{-3}\) in the denominator. \[ \frac{7^1}{7^{-3}} = 7^{1 - (-3)} = 7^{1 + 3} = 7^{4} \]
  4. Convert to rational exponents:

    • The expression \(7^{4}\) can also be represented as: \[ 7^{4} = 7^{\frac{4}{1}} \]

So the rational exponent for the new expression is \(\frac{4}{1}\).

Thus, the final answer is: The rational exponent for the new expression is 4.