To solve the equation 2x^2 + 10x - 6 = 0 using the quadratic formula:
a = 2, b = 10, c = -6
Plug these values into the quadratic formula:
x = (-10 ± √(10^2 - 4*2*(-6))) / (2*2)
x = (-10 ± √(100 + 48)) / 4
x = (-10 ± √148) / 4
x = (-10 ± 12.17) / 4
This gives us two possible solutions:
x = (-10 + 12.17) / 4 = 2.17 / 4 = 0.54
x = (-10 - 12.17) / 4 = -22.17 / 4 = -5.54
Therefore, the solutions to the equation 2x^2 + 10x - 6 = 0 are x = -5.54 and x = 0.54. Rounding to the nearest hundredths place, the solutions are x = -5.54 and x = 0.54.
Use the quadratic formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a, to solve the equation 2x2 + 10x − 6 = 0. Round to the nearest hundredths place.
x = −5.54 and x = 0.54
x = −0.54 and x = 5.54
x = −4.30 and x = −0.70
x = −22.17 and x = 2.17
1 answer
1 answer