To solve the quadratic equation \( 8x^2 + 10x = 10x - 4 \), we start by rearranging the equation to standard form:
\[ 8x^2 + 10x - 10x + 4 = 0 \]
This simplifies to:
\[ 8x^2 + 4 = 0 \]
Next, we can rewrite this as:
\[ 8x^2 = -4 \]
Dividing both sides by 8 gives:
\[ x^2 = -\frac{4}{8} = -\frac{1}{2} \]
To solve for \( x \), we take the square root of both sides:
\[ x = \pm \sqrt{-\frac{1}{2}} \]
We can express this as:
\[ x = \pm \sqrt{\frac{1}{2}} \cdot \sqrt{-1} = \pm \frac{1}{\sqrt{2}} \cdot i \]
This can be simplified further by rationalizing the denominator:
\[ x = \pm \frac{\sqrt{2}}{2}i \]
Therefore, the solutions of the quadratic equation in the form of \( a \pm bi \) is:
\[ x = 0 \pm \frac{\sqrt{2}}{2}i \]
So the solutions are:
\[ x = \frac{\sqrt{2}}{2}i \quad \text{and} \quad x = -\frac{\sqrt{2}}{2}i \]